Theorem 1 of F Distribution can be used to test whether the variances of two populations are equal, using the Excel functions and tools which follows. In order to deal exclusively with the right tail of the distribution, when taking ratios of sample variances from the theorem we should put the larger variance in the numerator of

In order to use this test, the following must hold:

- Both populations are normally distributed with a common variance
- Both samples are drawn independently from each other.
- Within each sample, the observations are sampled randomly and independently of each other.

**Excel Functions**: The following Excel function can be used to carry out this test:

**FTEST**(R1, R2) = two-tailed F-test comparing the variances of the samples in ranges R1 and R2 = the two-tailed probability that the variance of the data in ranges R1 and R2 are not significantly different.

Thus FTEST(R1, R2) = 2 ∙ FDIST(*x, df _{1}, df_{2}*) where

*df*= the number of elements in R1 – 1,

_{1}*df*

_{2 }= the number of elements in R2 – 1 and

*x = var1*/

*var2*where

*var1*is the variance of the data in range R1 and

*var2*= the variance of the data in range R2. FTEST is a two-tail test, while FDIST and FINV are one-tailed.

Also FTEST(R1, R2) = FDIST(*x, df _{1}, df_{2}*) + FDIST(1/

*x, df*), i.e. the sum of the right tail starting from

_{2}, df_{1}*x*and the left tail starting from 1/

*x*. This is true since FDIST(1/

*x, df*) = FDIST(

_{2}, df_{1}*x, df*).

_{1}, df_{2}This function ignores all empty and non-numeric cells.

Excel 2010/2013 also provide a new function F.TEST which is equivalent to FTEST (see Built-in Statistical Functions).

In addition Excel provides an **F-Test Two-Sample for Variances** data analysis tool which automates the process of comparing two variances.

**Example 1**: A company is comparing methods for producing pipes and wants to choose the method with the least variability. It has taken a sample of the lengths of the pipes using both methods as given in the table on the left of Figure 1.

We test the following null hypothesis:

H_{0}: *σ _{1} – σ_{2}* = 0 (equivalently:

*σ*; i.e. both methods have the same variability)

_{1}= σ_{2}and use the statistic

with 11, 14 degrees of freedom, as described in the right side of Figure 1. Since this is a two-tail test, we note

p-value = 2 * FDIST(*F, df _{1}, df_{2}*) = 2 * FDIST(1.85, 11, 14) = 0.279 > 0.05 =

*α*

*F*-crit = FINV(α/2, df_{1}, df_{2}) = FINV(.025, 11, 14) = 3.09 > 1.85 = *F*

Either of the above tests shows that there is no significant difference in the variance between the two methods with 95% confidence. Note that we needed to double the value for FDIST or halve α since these are two-tail tests.

Alternatively we can use FTEST which is a two-tail test:

FTEST(A4:A18, B4:B18) = .279 > 0.05 = *α*

.279 represents the sum of the area under the curve in the interval (-∞, 1/*F*), i.e. the left tail, plus the area under the curve in the interval (*F*, ∞), i.e. the right tail.

We can also use the **F-Test Two-Sample for Variances** data analysis tool:

**Figure 2 – Comparing variances using Excel’s data analysis tool**

This tool only performs a one-tail test, and so the p-value (0.1393) needs to be doubled to get 0.279, which is the same value we calculated in Figure 1.

Well explained. You really help me to understand Excel.

Thank you.

Rosalina, thanks very much for your comment. Charles