The **intraclass correlation** (ICC) assesses the reliability of ratings by comparing the variability of different ratings of the same subject to the total variation across all ratings and all subjects. The ratings are quantitative. We illustrate the technique applied to Likert scales via the following example.

**Example 1**: Four judges assess 8 types of wine for quality by assigning a score from 0 to 9 with the ratings given in Figure 1. Each judge tests each wine once. We would like to determine whether the wines can be judged reliably by different judges.

**Figure 1 – Data for Example 1**

We can see from the data that there is a fair amount of consistency between the ratings of the different judges with a few noticeable differences.

We will assume that the four judges are taken from a random sample of judges and use Excel’s Anova: Two Factor without Replication data analysis (i.e. a repeated measure analysis). The results are given in Figure 2.

**Figure 2 – Calculation of Intraclass Correlation**

Here the rows relate to the Between Subjects (Wines) and the columns relate to the Judges (who are the raters). The error term is Judge × Subjects. We have added row 29 which contains the calculation of the ICC (in cell I29) using the formula

=(J23-J25)/(J23+I24*J25+(I24+1)*(J24-J25)/(I23+1))

We will now explain this formula. From Definition 1 in Two Factor ANOVA without Replication we have the model

The intraclass correlation is then

Thus there are three types of variability:

var(*β*): variability due to differences in the subjects (i.e. the wines).

var(*ε*): variability due to differences in the evaluations of the subjects by the judges (e.g. judge B really likes wine 3, while judge C finds it to be very bad)

var(*α*): variability due to differences in the rating levels/scale used by the judges (e.g. judges B and C both find wine 1 to be the worst, but while judge C assigns wine 1 a Likert rating of 0, judge B gives it a bit higher rating with a 2).

Each of these can be estimated as follows:

var(*β*) = (*MS _{Row} – MS_{E}*)/

*k*= (26.89 – 2.28)/4 = 6.15

var(*ε*) = *MS _{E}* = 2.28

var(*α*) = (*MS _{Col} – MS_{E}*)/

*n*= (2.45 – 2.28)/8 = 0.02

where *n* = number of rows (i.e. subjects = wines for Example 1) and *k* = number of columns (i.e. raters = judges). A consistent (although biased) estimate of the intraclass correlation is therefore given by

*ICC* = 6.15/(6.15 + 2.28 + 0.02) = 0.728

This can also be expressed by

The high value of *ICC* shows there is a fair degree of agreement between the judges.

**Real Statistics Function**: The Real Statistics Resource Pack contains the following supplemental function:

**ICC**(R1) = intraclass correlation coefficient of R1 where R1 is formatted as in the data range B5:E12 of Figure 1.

For Example 1, ICC(B5:E12) = .728. This function is actually an array function which provides additional capabilities, as described in Intraclass Correlation Continued.

**Real Statistics Data Analysis Tool**: The **Reliability** data analysis tool supplied in the Real Statistics Resource Pack can also be used to calculate the ICC. We show how to use this tool in Intraclass Correlation Continued.

**Observation**: There are a number of other measures of ICC in use. We have presented the most useful of these measures above. Click here for information about these other versions of ICC.

**Observation**: We now show how to calculate an approximate confidence interval for the ICC. We start by defining the following

From these we calculate the lower and upper bounds of the confidence interval as follows:

Using these formulas we calculate the 95% confidence interval for ICC for the data in Example 1 to be (.434, .927) as shown in Figure 3.

**Figure 3 – ****95% confidence interval for ICC**

**Observation**: The ratings by the judges indicate the difficulty or leniency of the judge. The raters can also be questions in a test. In this case the rating corresponds to the difficulty or leniency of the question.

**Observation**: The measure of ICC is dependent on the homogeneity of the population of subjects being measured. For example, if the raters are measuring the level of violence in the general population, the value of var(*β*) may be high compared to var(*α*) and var(*ε*), thus making ICC high. If instead the raters are measuring levels of violence in a population of inmates from maximum security prisons, the value of var(*β*) may be low compared to var(*α*) and var(*ε*), thus making ICC low.

Could you help me understand that it shows “Using these formulas we calculate the 95% confidence interval for ICC for the data in Example 1 to be (.408, .950) as shown in Figure 3”, while in the excel L42/lower=0.434, L43/upper=0.927? Does that mean there are further calculations afterwards to get the 95% CI? Many thanks!

No, there is simply a typo. The confidence interval should read (.434, .927). I have now changed the webpage to reflect this.

Thanks for identifying this problem.

Charles

Thanks!

Hi Charles,

Thanks again.

How would we calculate a p-value for this?

Thanks

Paul,

If you are referring to the C(3,1) example, then I believe that it is the value in cell L23 of the Figure 5, although I am not 100% certain of this. This is different for the C(2,1) example.

Charles

Yeah I’m not sure either. I know that’s the p-value for the ANOVA, but I don’t know if that would also be the p-value for the ICC. Anyway, confidence intervals apparently are more informative than p-values, so maybe I’ll just stick with reporting that.

Hi,

Would it be possible to obtain this excel sheet so I don’t need to enter these formulas by hand?

Thanks

Paul,

Yes, please go to the webpage Download Workbook Examples.

Charles

Hi Charles,

Thank you for this excellent resource.

My question relates to converting scores to a composite score. For example, within a category I have 3 questions –

Category – Information

Q1 – Quality of information

Q2 – Quantity of information

Q3 – Presentation of information

Each of these questions are assessed based on a likert scale from 1-5. Can I use a mean of the 3 scores or would that not be methodologically sound?

Thank you!

Batul,

That approach seems reasonable, but, of course, it really depends on what you plan to do with the composite score.

Charles

Hi Charles,

I want to use the composite score to calculate the ICC between 4 raters.

Batul.

Hi Charles,

Our research team is trying to determine how to establish inter-rater reliability for a records review process we are undertaking. We have approximately 400 records and want to reliably review them to assess for experiences of adverse events, some of which need to be extrapolated from notes, evaluations etc. such as the experience of neglect.

To establish inter-rater reliability is there a gold standard number of records, or statistic to determine necessary sample size, we should all review to establish reliability? Also, is the intra-class correlation coefficient the appropriate statistic to be using in this case?

Thank you,

Vamsi Koneru

Vamsi Koneru,

You can determine the sample size required using the Real Statistics Power and Sample Size data analysis tool, as described on the website.

Charles

Thank you for your response, I will use this tool on the website. For our purposes, is the ICC the appropriate statistic to use?

Thank you, Vamsi

Vamsi,

You haven’t provided enough information to enable me to comment on whether the ICC is the correct statistics to use. In any case, the referenced webpage does provide information to help you determine whether this is an appropriate statistic to use.

Charles

Thanks for your response. Would you please let me know what other information you would need to determine if the ICC is the corrct statistic to use?

Thank you, Vamsi

Dear Charles,

I am wondering if ICC is the correct method of testing inter-rater reliability if you have 2 raters evaluating the same people using a continuous (count) variable. Each reviewer watches a video of the same people and counts the number of times they blink in 30 seconds. You never seem to get exactly the same count but they are close. Should we be using ICC to test inter rater reliability here or something else?

Thanks

Keith,

There are many other rating approaches out there, but it seems that ICC could be used.

Charles

Charles,

Thanks. I will try ICC. Is there a better one that you might know of? I cannot find any specifically addressing the issue of continuous ratings. Most are based on discreet choices (like Cohen’s Kappa) or are Likert scale based.

Thank you again for your assistance.

Keith,

Some use Krippendorf’s Alpha (https://en.wikipedia.org/wiki/Krippendorff%27s_alpha), but ICC is a good choice.

Charles

Dear Charles,

On a wine tasting of 10 wines by 11 tasters, I found

ICC(2,1)=0.20 with confidence interval (0.07:0.54) and ICC(2,11)=0.74 (0.46:0.93)

The low value for ICC(2,1) seems to suggest a very poor correlation for the individual scores, whereas the ICC(2,11) value and the confidence interval seem to tell me that the reliability of the average of the 11 scores is not too bad.

Can you help me with the interpretation of this apparent contradiction?

Thank you,

Erik

Erik,

This is discussed on the webpage http://www.real-statistics.com/reliability/intraclass-correlation/intraclass-correlation-continued/. It depends on which measure is closer to your needs. The ICC(2,1) measurement is the one that is most commonly used.

Charles

Hello Charles,

I am looking to find the ICC for a dataset where each of three judges rates each subject three times. Additionally, the ratings are binary. What changes would you suggest to be able to calculate a valid ICC?

Thank you,

Paul

Hello Paul,

Maybe I am missing something here. Why would each rater rate the same subject multiple times? Wouldn’t the rating be the same each time?

Charles

Hello Charles,

The ratings of a given rater can differ for a given subject because some of the subjects do not fall into either category perfectly, so it could be possible to rate the subject differently across repeated ratings. If people’s judgement was perfect each time, this variability wouldn’t arise, though. The design of the experiment, with multiple raters and multiple ratings of each subject, is similar to the design described in a paper posted elsewhere in these forums:

http://ptjournal.apta.org/content/74/8/777.short

Thank you,

Pawel

Hello Paul,

From what I see from a quick reading of the abstract of the referenced article, the ratings may differ because additional information is gained over time.

Unfortunately, I don’t have enough time now to delve into this issue further.

Charles

Dear Charles,

I have four raters that have rated 80 different companies on several different variables in a survey. Most variables consist of several questions combined to create the given variable. Each rater rates different companies and a different number of companies, i.e. one rater did cases 1 to 20, 2nd rater companies 21 to 35, 3rd rater companies 36 to 41 and the 4th rater companies 42 to 80. For example purposes, one of the variables being asked of in the survey is HPWS. I created a mean to create the HPWS from all the questions regarding HPWS in the survey. I then try to run ICC in spss creating four columns, one for each rater. I then put the mean number acquired for the companies rated by the raters under the appropriate column. However, what is different is that each company is rated only by one rater. My results are not positive needless to say. Am I missing something. Can I not run ICC for some reason?

Nicole,

I haven’t completely followed what you did, and perhaps I am missing something, but I don’t see how you can get anything meaningful if each company is rated by only one rater.

Charles

Okay, yes. This is what I was thinking. You can only compute ICC to determine agreement between raters if the raters are rating the same case, correct?

Nicole, that is correct.

Charles

Thank you so much for a terrific resource!

At the very top, you say “We illustrate the technique applied to Likert scales via the following example.” What if the scale is not Likert? Additionally, what if each rater is from a different company and their group uses an entirely different scale? What’s more, what if five different raters using five widely different scales or measurement or

grading also look at different criteria in order to come up with a “final grade”? There is surprising little reading material out there when it comes to scales that differ and scoring methods/criteria that differ. In my example, one rater may use a ratio scale that can go negative, like +100 to -100 and another just ranks in an ordinal rank order, and another may have a scale that is 1,800 down to 50.

I am trying to determine if one or more raters deviate from “assumed positive correlation” from the other rating groups (group movement overall consistency even if the row item variation is very extreme for each row item). Even with all the differences of rating and scales, I assume the various raters “have their rankings in a similar order” at the end of the day. The “between group” variation is very large on any one row item but the groups should rank each row item fairly consistently. I know the Kendall W can be used with three or more raters but can the scales be vastly different one rater to another? Would ICC work here? I thought about converting each group to a rank order but have not done so yet; I don’t think you can use ICC if you convert to ranks, true?

Thank you very much!

Kirk,

Some clarifications:

1. ICC can be used with non-Likert data. It is only the example that uses Likert data. ICC requires interval or continuous data. In the example Likert data is treated as interval data.

2. ICC can handle the case where one rater tends to be more severe than another and so give fewer higher scores, but I would doubt that it handles situations where one rater rates from 1 (low score) to 10 (high score) and another from 100 (low score) to 1 (high score). Do you really have a situation where this can happen?

The following website may be helpful:

http://www.ncbi.nlm.nih.gov/pmc/articles/PMC3402032/

Charles

Hello Charles,

Great site, thanks for trying to help us non-stat gurus understand this field. I have heard varying opinions on whether the ICC can be used for “Intra-rater reliability” rather than “Inter-rater reliability”. In other words, can ICC be used if there is just one judge who makes multiple (repeated) measurements on a number of subjects (in effort to demonstrate repeatability/reproducibility of the measuring tool)? If not, which test to do you recommend? (measuring intestinal length using a 3D software on 50+ patients, just one reader though). Thanks in advance for any advice!

Chuck,

ICC isn’t used if there is only one judge.

Since there is only one judge but multiple patients, I would expect that most the variability would relate to the differences between patients, which could be measured by the variance or standard deviation. I am not sure how you would squeeze out the variability due to the judge’s inconsistency in measuring (if indeed this is what you are interested in).

In any case, here are some other measurement techniques which may or may not be relevant to you: Bland-Altman, Cronbach’s Alpha, Gage R&R. All are described on the Real Statistics website (just enter the name in the Search box).

Charles

Hi Charles,

First of all thank you for your down to earth explanations. I do have a question. Can you do ICC on just one item for 5 raters/judges? SPSS seems to prevent you from doing that.

Any guidance will do.

Thank you.

Ray,

No. With only one subject ICC doesn’t really have any meaning.

Charles

I think this site is a wonderful resource, therefore I hope you dont mind some naive questions since I think I am on the cusp of understanding, but not quite there.

The actual value generated for the wines example:

ICC = 6.15/(6.15 + 2.28 + 0.02) = 0.728

what in layman’s terms might figure 0.728 represent ? (the wine testers had slightly/fairly/very homogenous opinions)?

Also, of the judges, judge b appears the most iconoclastic. But is there some measure whereby a judges mark could be compared to the others at which point it might be possible to make the conclusion that it goes beyond iconoclasm: namely (a) they know nothing about wine, or (b) they were actually judging different wines?

Similarly is there a standard numerical way of quantifying the level at which any wine might be said to generally ellicit divergent opinions (you either love it or you hate it)?

I suppose what I have difficulty with (owing to a lack of background in statistics rather than any lack of clarity in the site) is how to map a number of the terms you mention here, with the concepts I am interested in: namely measuring the homogeneity of a group of judges, the pattern of any particularly judge (compared to the others), and the degree to which a subject (in this case wine) tends to ellicit convergent or divergent opinions.

Two final simple questions – if there were two criteria for each of the judges when evaluating wine (e.g aroma and body) and there were therefore 2 scores from each judge per wine, would that affect how one went about using ICC. Also, if the judges were not that conscientious and forgot to record scores for some of the wines, would that affect the excel procedures?

Thanks anyway, for a wonderful site

Steve

Steve,

I actually have many of the same questions as you regarding ICC. It is not always clear how to interpret these measurements. If ICC is .9 then it is easy to see that it is high, but it is not so easy with lower values. The following website provides some guidelines, but I am sure that not all statisticians would agree with these guidelines. In any case, the article may be useful.

http://www.ncbi.nlm.nih.gov/pmc/articles/PMC3402032/

Regarding what to do when there are multiple criteria (eg aroma and body), you could create a composite score and calculate ICC on the composite score. Alternatively, you could calculate two ICC measurements based on each of the criteria. Since ICC is based on ANOVA you create a new ICC measurement based on an ANOVA model which takes both criteria into account (I have not tried to do this).

Charles

Dear Charles!

Thank you for your article. I am also very happy that seemingly the Q&A is still viral.

I would like to ask for your help as well.

I would like to determine the test-retest reliability of certain biomechanical parameters of a person’s postural stability.

The person was measured six times in bipedal stance eyes open and closed conditions, furthermore in a single limb stance. The measured parameters are usually differ in these conditions.

In my ICC analysis I considered the six trials as the six judge and the types of stance as 3 subjects. I committed the analysis separately for each parameters.

Do you think this approach is correct?

I have read in a study that they averaged results of trials thus increased ICC. In my case this would reduce judge number by the averaging number. What do you think of this approach? What is the importance of judge number?

Thank you for your answer in advance!

Gergely

Gergely,

Sorry, but I really don’t have enough information to answer your question. If the trials are done by the same person then the results won’t be independent which may defeat the purpose of the ICC analysis.

Charles

Hello sir,

Can you please help me with my inter annotator agreement? I want to compare two versions of a codingmodel, which contains 30 categories. My material is based on 39 different instructions. How can i best use the Cohen’s Kappa?

Joyce,

The following webpage shows how to do this:

http://www.real-statistics.com/reliability/cohens-kappa/

Charles

Hi,

I wonder whether the within subject standard deviation (Sw) can be calculated provided that the published article only provides the ICC value as well as the mean and SD for each of the replicated measurements?

Let’s say a study says that the intra-observer ICC of a thickness measurement is r=0.99 (one observer has repeated the thickness measurement on 10 subjects). It also provides the mean and SD for each of the repeated trial as:

Trial 1: Mean :361.95 SD=88.84 n=10

Trial 2: Mean:364.44 SD=92.84 n=10

Thanks

Hosein,

Sorry, but I am not sure which measurements you are referring to. In any case, ICC = var(b)/(var(a)+var(b)+var(e)). If you want to find the value of var(e) then you need to know the values of ICC, var(a) and var(b). You have the value of ICC, and so you need to know the values of var(a) and var(b). Now, var(b) = (MSRow-MSE)/k. It sounds like you have the values of MSRow and k. Thus var(b) has a value which depends on MSE (which is the same as var(e)), which means that so far you would need to use some algebra to solve for MSE. Finally, var(a) = (MSCol – MSE)/n. It sounds like you have n, but I am not sure whether you also have MSCol, in which case you won’t be able to find var(a).

Charles

hi Charles,

i am a person who understands very little of statistics, but am doing a research. my research is on 4 different formulae and if they could predict birth weight of the fetus accurately before being born, i compare this to the actual birth weight after birth.

i have arrived at the following table, can you please explain to me what i should infer from it (what does it mean)

Equations used – Intra Class Correlation -95% of ICC

Buchmann – 0.698 -0.599 to 0.769

Dare’s – 0.656 -0.419 to 0.777

Johnson’s – 0.682 -0.557 to 0.764

Hadlock’s – 0.607 -0.096 to 0.794

thanks

Sorry, but I can’t decipher the table. Presumably the names are the names of the raters. I can’t tell what the first number in each row represents. The next two numbers appear to be some sort of confidence interval.

Charles

Hello Charles

I am doing an analysis on coal ash. How it is done is that, a lab receives samples from the source A to do a precertified analysis and another sample from the source B to do a verification analysis. The analysis is done in replicates i.e there will be two results which are then averaged to have one number. I want to assess the variability between the replicates and the the average for Precertified and verification, as they are assumed to come from the same coal stockpile. I want to use ICC but not sure whether to use the ICC1 or ICC3. At the end i need to check the variablity between Precertified and verification as well as variability between rep 1 and rep 2 from both Precertified and verification. Kindly assist. thanks D

Sorry but I don’t completely understand the situation. What is playing the role of rater in this situation? Are you taking two replicates from source A and averaging them and also taking two samples from source B and averaging them? Does this mean that you have a total of 4 coal ash measurements? I am confused.

Charles

Hi Charles,

What does a 95% confidence interval for an ICC value physically mean? Could it be that you can have a 95% confidence in that ICC when it lies between the lower and upper limit? And why is there an upper limit? I would expect that the higher the ICC value the better. There is clearly something I do’nt understand.

By the way, I recalcalulated withe Excell the whole example 1 (4 judges, 8 wines) and want to report that in the formulas for g and h, I had to utilize the F.INV.RT function instead of FINV.

Thank you for answering. Your site is a great help for me

Erik

Erik,

Good to read that the site has been a great help.

A 95% confidence interval has the same meaning for ICC as for any other statistic. You can think of it as meaning that you can have 95% confidence that ICC lies between the lower and upper limits (although the actual meaning is a little more complicated). Even when the higher the ICC the better, there is still an upper limit.

F.INV.RT and FINV produce the same results. I have used FINV since Excel 2007 users don’t have access to the newer F.INV.RT function.

Charles

Charles,

Two more questions:

1 I held a wine tasting (n=k=7) and found ICC(2.1)=.449 (alpha 5%;.171-.823) and ICC(2.7)=.851 (5%, .590-.970). The ICC values are situated within the confidence interval and are thus not significant. I need a help to to interprete this conclusion. Which are the null and alternative hypotheses of the test?

2 What do you think of taking extreme looking scores for one or more wines out of the test?

Thank you again,

Erik

Erik,

1. The null hypothesis is that the population ICC = 0.

2. As long as you report that you have done that, I don’t see any problem with it.

Charles

Hi,

I need a help.

I do not know of this test is suitable for my situation or not.

I have 428 texts that are annotated by numbers 1,2,3,…,428 and I applied a sentiment analysis on these text and the results were positive 1 or negative -1 or 0. This analysis applied in two versions one in arabic texts and the other one translated English. So, I have two row contain the result of sentiment in each case. In this case, I can use Kappa I think.

However, In addition for that , I have 3 extra rows from 3 different annotators. I want to measure the similarity between these 5 rows. Is this text suitable for my case.

Thanks in advance.

If I understand things correctly, essentially you have 428 subjects to rate, 5 raters and ordered ratings. This is usually a good fit for Intraclass Correlation. The only problem is that you only have three ratings: -1, 0 and 1, and so I am not sure how robust the Intraclass Correlation in this case. Another possibility is Krippendorff’s Alpha, but I can’t recall whether this measurement has the same limitation.

Charles

Thank you for replying, My reaponse is between -1 to 1. So, the values are continuous between them. However, I used the ICC between 3 responsed and I got a negative value! and I read that ICC cannot be a negative value !!

but when I calculate it with all response I got 0.05 ? Is this relevant results

Without seeing your data I am not in a position to answer your question..

Charles

Hi Charles, may I apply ICC to the following scenario.

I set up a test that asks observers to look at pictures of two lines arranged perpendicular to each other, their task is to guess the how much the horizontal line measures as a percentage of the vertical line. I have measured the lines so I KNOW the correct answer.

I wish to analyse:

1. whether the observers agree with each other for each picture and whether this is statistically significant.

2. how far the observers deviate their scores from the true measurement and whether this occurs at certain horizontal:vertical length ratios.

As I understand it, all the observers must score the exact same slides and are randomly selected.

My main problems are:

1. Will ICC help answer the above questions.

2. How many slides are needed in the test to power the study p=0.05?

3. How many observers are needed to power the study for p=0.05?

Luckily I can create any number of slides and have the liberty to select up to 15 observers.

Any help would be much appreciated.

-YH Tham

PS the observers are given the following options to choose from 0%, 25%, 50%, 75%, 100%, 125%, 150%, 175%, 200%.

YH Tham,

1. I understand from “all the observers must score the exact same slides and are randomly selected” that all the slides are rated and that all the slides are rated by the exact same raters (who are randomly selected from a population of raters). If I understand this correctly then ICC class 2 can be used. (If different raters are randomly selected to rate the slides then ICC class 1 can be used.)

2. I don’t know of a way to calculate the power or sample size for ICC class 2. I can calculate the power and sample size for ICC class 1, but this approach is not applicable to class 2. I know that the ICC for class 1 is always less than or equal to the ICC for class 2.

3. I believe that the more observers (raters) the fewer slides need to be tested, but I can’t give any exact figures.

Charles

Thanks Charles, forgive me, I’m a little new to this. I’m not sure I understand.

As per my scenario:

I can create a bank of 300 slides (designated slide 1, slide 2, slide 3 etc up until 300). For each slide, I know the answer as I have measured the horizontal and vertical linear ratios. From this bank I can randomly select slides to create a test with ‘n’ number of slides.

I can also select ‘x’ number of observers/raters randomly to take a test. I have the ability to create a different test for each observer, or I can use the same test on each observer. Which would you prefer to satisfy the criteria for ICC class 1?

I guess, the real question is what do I need to do in order to make it easy to power the study from an ICC class 1 perspective. Then what numbers of ‘n’ and ‘x’ do I need to satisfy a p<0.05?

Kind regards

-YH Tham

PS Furthermore, I’m not sure whether to call ‘n’ or ‘x’ (as described above) ‘sample size’.

YH Tham,

I use k to represent the number of raters and n to represent the number of subjects (i.e. slides) being rated.

All three ICC classes assume that each subject is rated by the same number of raters, but if the same raters don’t rate all the subjects then it is the class 1 ICC that is used. It is assumed that the raters for each subject are selected at random from a pool of raters.

You can’t tell in advance which values to use for k and n to satisfy p < .05. The value of p is calculated after you perform the test. Charles

Thank you Charles, I can’t tell you how much you help people with this website.

My problem still boils down to the same issue in the end, I have is how to justify the values selected for ‘k’ and ‘n’ and I am never sure how to go about it. How many would you suggest? and on what basis?

Sorry once more for bothering you again, I promise I will leave you alone after your next reply! 🙂

Perhaps I am not completely understanding the nature of the difficulty that you are having, but the key is to determine what are the subjects/entities that are being rated and who/what are the raters. I am using n = the number of subjects and k = the number of raters (that rate each subject).

Charles

Hi Charles,

Thank you very much for your amazing work.

I have got a problem here,

I have 62 questions and 100 respondents (responses are in the form of Yes or No). And if the response is ‘Yes’, there is a score for that (Score changes from question to question). And if the response is ‘No’, score is zero irrespective of questions.

I am not getting which test can I perform on this data to check for Reliability, Agreement among respondents(raters). And let me know if any other test possible on this data.

Please help me with this.

Thank you very much

Bharatesh R S

If I understand correctly, then there is a numerical score for every question, namely some (presumably positive) number if the person answers Yes and 0 if the person answers No. If your goal is to check whether the scores for the 62 questions are consistent across all 100 raters then it seems like the ICC should work fine.

Charles

Thank you very much Charles.

Hi Professor,

I wonder if there is a possibility to use weightened Kappa for multiple experts. (Fleiss’ kappa, but weightened). If yes, it is possible to weight it not linearly, but quadratic, or some other way. You probably might say, that ICC is more suitable here, but I have only 5 categories (categorial type of data 0-1-2-3-4 and I cannot change/extend the ratings scale), and the matter of fact that difference between 3 and 4 is quite big(by definition of the category) and I want it to be considered in the inter-rater analysis.

The following articles might be helpful. I have not read them, but they seem to be related to your question.

https://www.researchgate.net/publication/24033178_Weighted_kappa_for_multiple_raters

http://www.sciencedirect.com/science/article/pii/S1572312711001171

Charles

Charles,

Which ICC I must use? (which case?)

As exposed in Doros (2010) – Design Based on Intra-Class Correlation Coefficients, we have:

Case 1 – each target is rated by different raters

Case 2 – the same raters rate each target

Case 3 – all possible raters rate each target

similar in Shrout (1979)-Intraclass Correlations: Uses in Assessing Rater Reliability, page 421 after the table

I have 2 instruments (methods to measure), and I am measuring the RR intervals in a number of patients.

I also have to choose a random beat (heart beat) in each record, p.e. the beat 10 of each record, or choose a random number of beat in each record, p.e. choose 10 beats (2nd, 4th, 8th, 12th, …) in each record.

Do you agree with me with these identities or do you have another idea?

target = patient

raters = beat

judge = method

Paulo,

Sorry but I don’t understand your example. I didn’t define “target” and judge and rater are usually the same thing.

Charles

Hi Charles,

I have a situation that may be similar to Steve’s scenario above. In our scenario, two raters are judging the performance of 7 students over a 5 to 8 week period where they meet three times per week to discuss cases in groups. After the 5 to 8 weeks, each rater evaluates each student based on multiple qualities (how well did they listen, how well did they speak, how well did they show respect for others, etc.). I guess this would be like having the rater’s in your example rate the color, aroma, and taste for each wine rather than simply assigning a single number between 0 and 9 for how “good” the wine is. My question is…if each of the qualities is weighted equally, is it appropriate to use each students average score from each rater for the ICC or is there a different analysis that could be done to preserve this additional dimension of measurement?

Perhaps the following paper on multivariate ICC could be helpful:

http://files.eric.ed.gov/fulltext/ED038728.pdf

Charles

Hi there! my situation looks like this: Two groups of people A and B had two texts to rate: group A rated texts A1 and A2, and group B rated texts B1 and B2. There were 9 raters in group A and 7 in group B (but two of them failed to mark B2). I want to find the IRR of the marks that have been given by the raters. I have done the ICC for texts A1 and A2 and also for B1 and B2. Now I would like to do the same for texts A1 and B2, and A2 and B1, but spss won’t let me because the amount of raters in groups A and B is different. Any suggestions?? Thanks!

Marta,

I don’t know an accepted way of handling the situation with unequal number of raters. The following is a possible approach, but I have no experience as to whether this approach gives useful results or whether this approach matches your situation.

Suppose there are 9 raters for group A and 7 raters for group B and suppose that we can create an IRR measure if group A had only 7 raters (equal number of raters). Since there are C(9,7) = 36 ways of choosing 7 of the 9 raters, calculate the IRR measure for all 36 ways of 7 raters for A with the 7 raters for B. Then take the average of these 36 measures as your IRR.

Charles

What if there were multiple measurements per observer? Would you take the mean of each and proceed?

Steve,

If you follow this approach then you will be calculating a measurement of the agreement between raters of their mean rating. This may be sufficient for your needs.

If you want to take the multiple measurements per rater I would guess that you would need to use a version of ICC based on ANOVA with repeated measurements. Unfortunately I wasn’t able to quickly find a reference for this. Perhaps someone who is following this issue with us online has a reference.

Charles

I am struggling to understand how this provides a measure of reliability since the value seems totally dominated by the diversity of the population, as you mention above. If, for example, I have two sample sets on the same 5 point scale, and in one set the judges scored everything within a 2 point range (scores of 2’s or 3’s) and in the other set the scores covered the whole range, the ICC for the first set would be lower than the second set regardless of which sample set was scored more reliably.

Why I try to assess the reliability of the judges ratings using the Class 3 ICC I see consistent increase of the ICC, but again it doesn’t seem to correlate with what I would consider true reliability.

Thanks for you time.

Regards,

Christian

Hi Prof,

I seek your help regarding a repeatability test.

I’m conducting an experiment where there are 5 fixed examiners. The examiners will be required to plot on a software the thickness of a body tissue. On each body tissue sample, there will be 1000 points along the whole sample. The software will then generate the thickness of the 1000 points along the tissue.

I want to find the repeatability of these plots within the examiner himself and between the 5 examiners.

Is it right for me to use the ICC for the repeatability analysis?

I hope you can clear my doubts.

Thank you for your time.

Regards

Vincent

Vincent,

Repeatability refers to a single person/instrument measuring the same item repeatedly. This doesn’t sound like the situation that you describe. What you describe seems more like “reliability”. ICC can be used for this purpose.

Charles

And why is there a “AB21 +” in the denominator in AD26? There is no d in the equation for lower above.

Why is it in Excel equation AD24: AB23 for g? should it not be AB22 for d’ in the equation?

Thank you for the explanation!

Question: The left side of the formula for d= doesn’t match the right side. Seems to be a k missing in the denominator?!

I meant numerator…

actually the k should not be there on the right side.

Thank you for this wonderful explanation. How this ICC formula applies to the calculation of ICC for Hierarchical Linear Models or Mixed Models???

Trinto,

I have not yet included hierarchical models and mixed models in the website. I plan to this in the future.

Charles

Hi,

Thanks for this post!

I’ve got issues to understand the following sentences since judges E and F don’t exist. Moreover, the two sentences are in contradiction with each other… and with reality.

” var(ε): […] judge E finds wine 1 terrible, while judge F loves wine 1)”

” var(α): […] judges E and F both find wine 1 to be the best, but while judge E assigns wine 1 a Likert rating of 9, judge F gives it a rating of 6).”

Thanks for enlightening me!

TS,

Thanks for pointing out the problem with the description given. I have modified the two sentences. I hope that the new version is less confusing and helps explain things better.

Charles

Dear Prof ,

Does your software calculate the 95% confidence interval for ICC?

Could you please show me how?

Thank you

Albert,

A description of how to calculate the 95% confidence interval for ICC is given on the webpage http://www.real-statistics.com/reliability/intraclass-correlation/intraclass-correlation-continued/ (see esp. the Class 2 Model). This calculation is not yet included in the software, although it will be included shortly.

Charles

Will this statistic work with a non-random group of raters? I have the entire population of raters and would like to test their reliability. Thank you in advanced!

Bryan,

If you are evaluating specific raters use the class 3 version of ICC as described in http://www.real-statistics.com/reliability/intraclass-correlation/intraclass-correlation-continued/.

Charles

Sir

Is there any common accepted criteria or critical value for ICC ?

Thanks for your help. What if you don’t have 4 raters but instead have 2? Would you still use the ANOVA?

Jes,

ANOVA can be used with 2 groups. In this case it is equivalent to a t-test. With two raters you can also use Cohen’s kappa.

Charles

Thank you! One last question–what would be the p-value for the ICC? Would it be the value in L23?

Jen,

The p-value that is reported is the one that you identified but this is not very useful. I have now updated the webpage with the confidence intervals for ICC. This will be more meaningful.

Charles

I can’t find the function “intraclass correlation coefficient” anywhere. Where should we find it starting from the “ctrl+m” window ?

Langlois,

Since ICC is a worksheet function and not a data analysis tool you can’t access it by pressing Ctrl-m. Instead simply enter the function in a worksheet by typing =ICC(R1) in any cell where R1 is the range containing the data.

Charles

What does var(B) =?

What does var(alpha) =?

What does var(E) = ?

How do you figure that out from the information given?

Dear Hailey,

I have just updated the Intraclass Correlation webpage with a better description of how to compute var(alpha), var(beta) and var(epsilon).

Charles

Thank you: A great explanation in few words.